5sin^2x+5sinx+4cos^2x=0

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Solution for 5sin^2x+5sinx+4cos^2x=0 equation: 


Simplifying
5sin2x + 5sinx + 4cos2x = 0

Reorder the terms:
4cos2x + 5insx + 5in2sx = 0

Solving
4cos2x + 5insx + 5in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5insx' to each side of the equation.
4cos2x + 5insx + -5insx + 5in2sx = 0 + -5insx

Combine like terms: 5insx + -5insx = 0
4cos2x + 0 + 5in2sx = 0 + -5insx
4cos2x + 5in2sx = 0 + -5insx
Remove the zero:
4cos2x + 5in2sx = -5insx

Add '-5in2sx' to each side of the equation.
4cos2x + 5in2sx + -5in2sx = -5insx + -5in2sx

Combine like terms: 5in2sx + -5in2sx = 0
4cos2x + 0 = -5insx + -5in2sx
4cos2x = -5insx + -5in2sx

Divide each side by '4os2x'.
c = -1.25ino-1s-1 + -1.25in2o-1s-1

Simplifying
c = -1.25ino-1s-1 + -1.25in2o-1s-1

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